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Mastering JavaScript Functional Programming

You're reading from   Mastering JavaScript Functional Programming Write clean, robust, and maintainable web and server code using functional JavaScript and TypeScript

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Product type Paperback
Published in Apr 2023
Publisher Packt
ISBN-13 9781804610138
Length 614 pages
Edition 3rd Edition
Languages
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Author (1):
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Federico Kereki Federico Kereki
Author Profile Icon Federico Kereki
Federico Kereki
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Toc

Table of Contents (17) Chapters Close

Preface 1. Chapter 1: Becoming Functional – Several Questions 2. Chapter 2: Thinking Functionally – A First Example FREE CHAPTER 3. Chapter 3: Starting Out with Functions – A Core Concept 4. Chapter 4: Behaving Properly – Pure Functions 5. Chapter 5: Programming Declaratively – A Better Style 6. Chapter 6: Producing Functions – Higher-Order Functions 7. Chapter 7: Transforming Functions – Currying and Partial Application 8. Chapter 8: Connecting Functions – Pipelining, Composition, and More 9. Chapter 9: Designing Functions – Recursion 10. Chapter 10: Ensuring Purity – Immutability 11. Chapter 11: Implementing Design Patterns – The Functional Way 12. Chapter 12: Building Better Containers – Functional Data Types 13. Answers to Questions 14. Bibliography
15. Index 16. Other Books You May Enjoy

Chapter 1, Becoming Functional – Several Questions

1.1 TypeScript, please! The following are the fully annotated versions of the code in the chapter. This is the code for the factorial functions:

// question_01_typescript_please.ts
function fact(n: number): number {
  if (n === 0) {
    return 1;
  } else {
    return n * fact(n - 1);
  }
}
const fact2 = (n: number): number => {
  if (n === 0) {
    return 1;
  } else {
    return n * fact2(n - 1);
  }
};
const fact3 = (n: number): number =>
  n === 0 ? 1 : n * fact3(n - 1);

This is the code for the spreading examples:

// continued...
function sum3(a: number, b: number, c: number): number {
  return a + b + c;
}
const x: [number, number, number] = [1, 2, 3];
const y = sum3(...x); // equivalent to sum3(1,2,3)
const f = [1, 2, 3];
const g = [4, ...f, 5];...
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