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Debunking C++ Myths

You're reading from   Debunking C++ Myths Embark on an insightful journey to uncover the truths behind popular C++ myths and misconceptions

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Product type Paperback
Published in Dec 2024
Publisher Packt
ISBN-13 9781835884782
Length 226 pages
Edition 1st Edition
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Authors (2):
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Ferenc Deak Ferenc Deak
Author Profile Icon Ferenc Deak
Ferenc Deak
Alexandru Bolboaca Alexandru Bolboaca
Author Profile Icon Alexandru Bolboaca
Alexandru Bolboaca
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Table of Contents (15) Chapters Close

Preface 1. Chapter 1: C++ Is Very Difficult to Learn 2. Chapter 2: Every C++ Program Is Standard-Compliant FREE CHAPTER 3. Chapter 3: There’s a Single C++, and It Is Object-Oriented 4. Chapter 4: The Main() Function is the Entry Point to Your Application 5. Chapter 5: In a C++ Class, Order Must There Be 6. Chapter 6: C++ Is Not Memory-Safe 7. Chapter 7: There’s No Simple Way to Do Parallelism and Concurrency in C++ 8. Chapter 8: The Fastest C++ Code is Inline Assembly 9. Chapter 9: C++ Is Beautiful 10. Chapter 10: There Are No Libraries For Modern Programming in C++ 11. Chapter 11: C++ Is Backward Compatible ...Even with C 12. Chapter 12: Rust Will Replace C++ 13. Index 14. Other Books You May Enjoy

The dark orders of C++

There is one dark corner of the C++ language that is rarely touched by sunlight, and if a piece of code from these depths surfaces by any chance, a gang of hardcore developers immediately jumps on it and refactors it into digestible bits and bytes. Let’s consider, for example, the very simple case of why the a[2] and 2[a] expressions are equivalent when in C++, and a is an array of objects:

int main() {
    int a[16] = {0};
    a[2] = 3;
    3[a] = 4;
}

The preceding piece of code, despite the fact that it looks ugly, actually compiles. The reason is the following: in C++, the operator [] array subscript is defined in terms of pointer arithmetic. The a[i] expression is translated by the compiler into *(a + i), where a is a pointer to the first element of the array and i is the index. The i[a] expression at the end is also translated to the *(i + a) expression, where i is the index and a is...

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