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Demystifying Cryptography with OpenSSL 3.0

You're reading from   Demystifying Cryptography with OpenSSL 3.0 Discover the best techniques to enhance your network security with OpenSSL 3.0

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Product type Paperback
Published in Oct 2022
Publisher Packt
ISBN-13 9781800560345
Length 342 pages
Edition 1st Edition
Languages
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Author (1):
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Alexei Khlebnikov Alexei Khlebnikov
Author Profile Icon Alexei Khlebnikov
Alexei Khlebnikov
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Table of Contents (20) Chapters Close

Preface 1. Part 1: Introduction
2. Chapter 1: OpenSSL and Other SSL/TLS Libraries FREE CHAPTER 3. Part 2: Symmetric Cryptography
4. Chapter 2: Symmetric Encryption and Decryption 5. Chapter 3: Message Digests 6. Chapter 4: MAC and HMAC 7. Chapter 5: Derivation of an Encryption Key from a Password 8. Part 3: Asymmetric Cryptography and Certificates
9. Chapter 6: Asymmetric Encryption and Decryption 10. Chapter 7: Digital Signatures and Their Verification 11. Chapter 8: X.509 Certificates and PKI 12. Part 4: TLS Connections and Secure Communication
13. Chapter 9: Establishing TLS Connections and Sending Data over Them 14. Chapter 10: Using X.509 Certificates in TLS 15. Chapter 11: Special Usages of TLS 16. Part 5: Running a Mini-CA
17. Chapter 12: Running a Mini-CA 18. Index 19. Other Books You May Enjoy

Deriving a key from a password on the command line

Producing an encryption key from a password on the command line can be done using the openssl kdf subcommand. This is a new subcommand that was added in OpenSSL 3.0. You can read its documentation on the openssl-kdf man page:

$ man openssl-kdf

Before deriving the key, let’s generate 128-bit salt:

$ openssl rand -hex 16
cf0e0acf943629ecffea41c87bab94d4

Now we can derive a 256-bit key suitable for symmetric encryption. Let’s use the Scrypt KDF. OWASP recommended brute-force-resistant settings and the password SuperPa$$w0rd:

$ openssl kdf \
  -keylen 32 \
  -kdfopt 'pass:SuperPa$$w0rd' \
  -kdfopt hexsalt:cf0e0acf943629ecffea41c87bab94d4 \
  -kdfopt n:65536 -kdfopt r:8 -kdfopt p:1 \
  SCRYPT
D0:3D:31:A1:A2:2A:F6:68:99:B3:02:22:60:3B:D7:21:5B:15:5B:80:2B:85:33:36:E6:3B:AB:F9:EE:8F:FE:C7

Note that the command-line argument containing the password...

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