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MySQL 8 Cookbook

You're reading from   MySQL 8 Cookbook Over 150 recipes for high-performance database querying and administration

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Product type Paperback
Published in Jan 2018
Publisher
ISBN-13 9781788395809
Length 446 pages
Edition 1st Edition
Tools
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Author (1):
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Karthik Appigatla Karthik Appigatla
Author Profile Icon Karthik Appigatla
Karthik Appigatla
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Table of Contents (15) Chapters Close

Preface 1. MySQL 8 - Installing and Upgrading FREE CHAPTER 2. Using MySQL 3. Using MySQL (Advanced) 4. Configuring MySQL 5. Transactions 6. Binary Logging 7. Backups 8. Restoring Data 9. Replication 10. Table Maintenance 11. Managing Tablespace 12. Managing Logs 13. Performance Tuning 14. Security

Grouping results (aggregate functions)


You can group the results using the GROUP BY clause on a column and then use AGGREGATE functions, such as COUNT, MAX, MIN, and AVERAGE. You can also use the function on a column in a group by clause. See the SUM example where you will use the YEAR() function.

How to do it...

Each of the previously-mentioned aggregate functions will be introduced to you here in detail.

COUNT

  1. Find the count of male and female employees:
mysql> SELECT gender, COUNT(*) AS count FROM employees GROUP BY gender;
+--------+--------+
| gender | count  |
+--------+--------+
| M      | 179973 |
| F      | 120051 |
+--------+--------+
2 rows in set (0.14 sec)
  1. You want to find the 10 most common first names of the employees. You can use GROUP BY first_name to group all the first names, then COUNT(first_name) to find the count inside the group, and finally the ORDER BY count to sort the results. LIMIT these results to the top 10:
mysql> SELECT first_name, COUNT(first_name) AS count...
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